Abstract |
This study elucidates the formation mechanism of SnO plate observed during the precipitation reaction of a SnCl2 aqueous solution. Sn21Cl16(OH)14O6 and Sn6O4(OH)4 precipitates was formed at pH=3~5 and at pH=11, respectively. When the pH was in the range of 11.5~12.5, the Sn6O4(OH)4 precipitates dissolved into HSnO2 - [Sn6O4(OH)4+4OH-=6HSnO2 -+2H+] and dissolved HSnO2 - ions reprecipitated to SnO plate [HSnO2 -+H+=SnO+H2O]. The Sn6O4(OH)4 precipitates completely transformed into SnO plate through a repeated process of dissolution-precipitation in the range of pH=11.5~12.5. |
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Key Words |
oxide, chemical synthesis, precipitates, X-ray diffraction, reaction mechanism |
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